Shortest Code to Sort 3 Numbers known to man?

sort3.asm

%include "asm_io.inc"

extern _printf

segment data align=4 class=data use32
EnterOne			db		"Enter number 1: ", 0
EnterTwo			db		"Enter number 2: ", 0
EnterThree			db		"Enter number 3: ", 0
FormattedAnswer		db		"%d %d %d", 0

segment bss align=4 class=bss use32
_a		resd	1
_b		resd	1
_c		resd	1

segment text align=1 class=code use32
	global _main
_main:
	enter	0, 0					; setup routine
	pusha
	
enter_number_one:
	mov		eax, EnterOne
	call	print_string			; printf("Enter number 1: ");
	call	read_int				; scanf("%d", &a);
	mov		[_a], eax
	
enter_number_two:
	mov		eax, EnterTwo
	call	print_string			; printf("Enter number 2: ");
	call	read_int				; scanf("%d", &b);
	mov		[_b], eax
	
enter_number_three:
	mov		eax, EnterThree
	call	print_string			; printf("Enter number 3: ");
	call	read_int				; scanf("%d", &c);
	mov		[_c], eax
	
load:
	mov		eax, [_a]
	mov		ebx, [_b]
	mov		ecx, [_c]
	
move1:
	cmp		eax, ebx
	jle		move2
	xchg	eax, ebx
	
move2:
	cmp		eax, ecx
	jle		move3
	xchg	eax, ecx
	
move3:
	cmp		ebx, ecx
	jle		print_result
	xchg	ebx, ecx

print_result:
	push	ecx
	push	ebx
	push	eax
	push	FormattedAnswer
	call	_printf
	add		esp, 10h
	call	print_nl
	
	popa
	mov		eax, 0
	mov		ebx, 0
	mov		ecx, 0
	leave
	ret

sort3.c

#include <stdio.h>

inline void xchg(void *v1, void *v2)
{
__asm__ (\
   "movl %0, %%eax\n"\
   "movl %1, %%ebx\n"\
   "xchgl %%ebx, %%eax\n"\
   "movl %%eax, %0\n"\
   "movl %%ebx, %1\n"\
   : : "r"(v1), "r" (v2));
}

int main()
{
	int a, b, c;
enter_number_one:
	printf("Enter number 1: ");
	scanf("%d", &a);

enter_number_two:
	printf("Enter number 2: ");
	scanf("%d", &b);

enter_number_three:
	printf("Enter number 3: ");
	scanf("%d", &c);

move1:
	if (a > b)
		xchg(a, b);
move2:
	if (a > c)
		xchg(a, c);
move3:
	if (b > c)
		xchg(b, c);

print_result:
	printf("%d %d %d\n", a, b, c);
    return 0;
}