Open random website based on command line arguments

stumble.py

#! /usr/bin/env python
from random import choice
import os
import webbrowser
if os.sys.version_info[0] < 3:
    from urllib import urlopen
else:
    from urllib.request import urlopen


def search(terms, exclude=('bing', 'microsoft', 'msn', 'twitter', 'live.com')):
    qurl = "http://www.bing.com/search?q="+"+".join(terms)+"&go=&qs=n&form=QBRE&pq=firefox&sc=0-0&sp=-1&sk="
    qpage = urlopen(qurl).read().decode('UTF-8')
    a = 0
    searchlist = []
    while True:
        linkhead = qpage[a::].find("href=\"http")+a
        if linkhead == a-1:
            break
        linktail = qpage[linkhead+20::].find("\"")+linkhead+20
        a = linktail
        link = qpage[linkhead+6:linktail]
        ignore = False
        for x in exclude:
            if x in link:
                ignore = True
        if not ignore:
            searchlist.append(link)
            print(link)
    return searchlist


def random_site(total_terms, n=5):
    terms = []
    print("Total terms="+str(total_terms))
    while len(total_terms) <= n:
        total_terms+=total_terms
    for i in range(n):
        terms.append(choice(total_terms))
        total_terms.remove(terms[-1])
        terms[-1]=terms[-1].replace(" ","+")
    print("terms:"+str(terms))
    return choice(search(terms))

#random_site(os.sys.argv[1::])
webbrowser.open(random_site(os.sys.argv[1::]))