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@RH2
Created January 29, 2013 19:48
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1.R1 is in series with D1,C1,Lamp. Lamp,C1,D1 are in parrallel with each other.
2.L1 is in parallel with Neon Lamp.SW1 and R1 are in series
3.Guaranteed Same Voltage: all components.
Guaranteed Same Current: Voltage is not guaranteed to be the same, so current is not guaranteed to be the same accross all components.
4. Yes, I would expect the potential stored in the battery to be decimated as the voltage does work. This explains why batteries become useless if they are not recharged
5.9V*3A=27Watts dissipated. 3ohms resistance. 9V=3A*_Ohms
6.when in series add the voltages. the circuit on the left would have a Voltage of 9V. When in parallel the main circuit would be 6V, and it would try to charge the 3V battery. Which might destroy the voltage source in the real world.
7.When you add currents in series (figure on the left): The rest of the series circuit will have the greatest amount of current available. In this case, that would be 6A.
when you add currents in parrallel (figure on the right): The currents add, so the circuit will be ~8A.
8. (1/2+1+1/3)^-1 Ohms = 0.54545454545Ohms
24V=1 Ohm*_A;Amps through this element:24A
24V=2 Ohm*_A;Amps through this element:12A
24V=3 Ohm*_A;Amps through this element:8 A
9.110V=2.5 Ohms * _ A =44A
44A*110V= 4840Watts
220V=2.5 Ohms * _ A = 88A
88A*220V=19360V
10. _V=12 Ohms*7A; 84V total power dissipation: 84*7=588W
V=I*R
6*7=42 Volts | 7*42=294Watts
4*7=28 Volts | 7*28=196Watts
2*7=14 Volts | 7*14=98Watts
294W+196W+98W=588W
11. V=8kΩ*5mA; 40V total power dissipation: 40*.005=0.2W
5000Ω*.005A=25 Volts | 0.125W
1000Ω*.005A=5 Volts | 0.025W
2000Ω*.005A=10 Volts | 0.05W
12. R1= AΩ R2= 3AΩ
Total resistance 4AΩ
A is a constant
13. 10V=10kΩ*_A; A=.001 or 1mA
1000Ω*.001A=1V
3000Ω*.001A=3V
6000Ω*.001A=6V
14. Resistor1(left)=3CΩ Resistor2(right)=CΩ
C is a constant
15. total resistance: (1/400+1/730+1/910)^-1=201.25729001Ω
total resistance 40+73+91=204
r.alternative/(r.this+r.alternative)
R.top = (40/204 = 0.19607843137) (^-1)= 5.10000000007
1-0.19607843137=0.80392156863= 80.392156863%
R.mid = (73/204 = 0.35784313725) (^-1)= 2.79452054798
1-0.35784313725=0.64215686275= 64.215686275%
R.bottom= (90/204 = 0.44117647058) (^-1)= 2.26666666671
1-0.44117647058=0.55882352942= 55.882352942%
total resistance:
r.top&r.mid = 25.841
r.top&r.bottom = 27.786
r.mid&r.bottom = 40.506
FINAL ATTEMPT
r.top =50.314%
r.mid =27.569%
r.bottom=22.116^
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