Tokenizing a string based on a set of delimiters into a dynamic array in C
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#include <stdio.h> | |
#include <stdlib.h> | |
#include <string.h> | |
size_t tokenize(const char *s, const char *delim, char ***tokenarray) | |
{ | |
size_t size = 0, capacity = 4, wordlen; | |
const char *begin = s, *end; | |
char **tokens = malloc(capacity * sizeof(char *)); | |
do { | |
begin += strspn(begin, delim); | |
if(!*begin) | |
break; | |
end = strpbrk(begin, delim); | |
wordlen = end ? (size_t)(end - begin) : strlen(begin); | |
if(size == capacity) { | |
capacity = capacity * 3 / 2; | |
tokens = realloc(tokens, capacity * sizeof(char *)); | |
} | |
memcpy(tokens[size] = malloc(wordlen + 1), begin, wordlen); | |
tokens[size++][wordlen] = 0; | |
} while((begin = end)); | |
*tokenarray = tokens; | |
return size; | |
} | |
int main(void) | |
{ | |
const char *str = "The quick brown fox jumps over the lazy dog.\n"; | |
char **tokens; | |
size_t numtok; | |
numtok = tokenize(str, " .\n", &tokens); | |
for(size_t i = 0; i < numtok; i++) { | |
printf("got <%s>\n", tokens[i]); | |
} | |
for(size_t i = 0; i < numtok; i++) { | |
free(tokens[i]); | |
} | |
free(tokens); | |
} |
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