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August 9, 2021 02:12
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Sort Colors LeetCode
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/* | |
Given an array nums with n objects colored red, white, or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white, and blue. | |
We will use the integers 0, 1, and 2 to represent the color red, white, and blue, respectively. | |
You must solve this problem without using the library's sort function. | |
Example 1: | |
Input: nums = [2,0,2,1,1,0] | |
Output: [0,0,1,1,2,2] | |
Example 2: | |
Input: nums = [2,0,1] | |
Output: [0,1,2] | |
Example 3: | |
Input: nums = [0] | |
Output: [0] | |
Example 4: | |
Input: nums = [1] | |
Output: [1] | |
Constraints: | |
n == nums.length | |
1 <= n <= 300 | |
nums[i] is 0, 1, or 2. | |
Follow up: Could you come up with a one-pass algorithm using only constant extra space? | |
*/ | |
/** | |
* @param {number[]} nums | |
* @return {void} Do not return anything, modify nums in-place instead. | |
*/ | |
var sortColors = function(nums) { | |
let a = 0; | |
let b = 0; | |
let len = nums.length; | |
for (let i = 0; i < nums.length; i++) { | |
if (nums[i] === 0) { | |
nums[i] = 2; | |
nums[b++] = 1; | |
nums[a++] = 0; | |
} else if (nums[i] === 1) { | |
nums[i] = 2; | |
nums[b++] = 1; | |
} else { | |
nums[i] = 2; | |
} | |
} | |
}; | |
const nums = [2,0,2,1,1,0]; | |
console.log(sortColors(nums)); |
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