Created
October 13, 2018 20:59
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Demonstration of the power of simple dynamic programming using the fibonacci sequance
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local NUM_TO_CALC = 10 | |
print("Fib1 - uses 'brute-force recursive method':") | |
print("-------------------------------------------") | |
local called = {} | |
-- hashmap to store call statistics | |
local function fib(n, depth) | |
depth = depth or 1 | |
-- if no depth is provided, then it is 1 | |
print(string.rep(" ",depth)..tostring(n)) | |
-- print depth number of spaces, then the number we are calculating | |
called[n] = called[n] and called[n]+1 or 1 | |
-- update call stats, called[n] is incremented | |
-- (or initialized to 1) | |
return | |
n==1 and 1 or -- 1 if n==1 | |
n==2 and 1 or -- 1 if n==2 | |
fib(n-1, depth+1) + fib(n-2,depth+1) | |
-- the sum of the prev. 2 else | |
-- depth is incremented here | |
end | |
local start = os.clock() | |
print("Fib("..tostring(NUM_TO_CALC)..")="..tostring(fib(NUM_TO_CALC))) | |
local dt = (os.clock() - start)*1000 | |
print("Elapsed "..tostring(dt).." seconds") | |
print("Call stats: ") | |
for k,v in pairs(called) do | |
print("Fib("..tostring(k)..") calculated "..tostring(v).." times") | |
end | |
print("\n") | |
--------------------------------------------- | |
print("Fib2 - uses caching of the results:") | |
print("-----------------------------------\n") | |
local cache = {} | |
local function fib(n) | |
if n==1 or n==2 then | |
return 1 | |
end | |
if cache[n] then | |
return cache[n] | |
end | |
local a = cache[n-1] or fib(n-1) | |
local b = cache[n-2] or fib(n-2) | |
local ret = a+b | |
cache[n] = ret | |
return ret | |
end | |
local start = os.clock() | |
print("Fib("..tostring(NUM_TO_CALC)..")="..tostring(fib(NUM_TO_CALC))) | |
local dt = (os.clock()-start)*1000 | |
print("Elapsed "..tostring(dt).." second") |
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