Program to find second maximum of n numbers without using arrays in Java

Logic.txt

Let's see Logic behind the code🤘

We have declared four variables ..
curr = Current element
first = Will be largest number 
second = Will be second max number
i = So that we can break the while loop

while(i==1) 
-> It checks whether i is 1 or not.
-> If yes goes inside the loop
-> If we enter -1 that is we are done for elements [In short we have entered all elements]. Now we need to break the loop 
    -> So now we will set i = 0 and we will break the loop

Let's assume that our inputs are 5 , 6 , 8  , 7 and -1 [=1 to break the loop]
curr = 5
first = curr
second = curr

Now we enter the loop
-> And we have now 6 as our curr value [curr = 6]
-> We check whether curr = -1 is true or not. [False]
-> Second Condition :
    -> (curr > first) [6 > 5] [True]
        -> second = 5
        -> first = 6

curr = 6
first = 6
second = 5


Now we again enter the loop
-> And now we have 8 as our curr value [curr = 8]
-> We check whether curr = -1 is true or not. [False]
-> Second Condition :
    -> (curr > first) [8 > 6] [True]
        -> second = 6
        -> first = 8

curr = 8
first = 8
second = 6


Now we again enter the loop
-> And now we have 7 as our curr value [curr = 7]
-> We check whether curr = -1 is true or not. [False]
-> Second Condition :
    -> (curr > first) [7 > 8] [False]
    
-> Third Condition :
    -> (curr > second) [7 > 6] [True]
        -> second = curr

curr = 7
first = 8
second = 7

Now we again enter the loop
-> And now we have -1 as our curr value [curr = -1]
-> We check whether curr = -1 is true or not. [True]
    -> i = 0 
    -> break;
    
-> As now i is 0 we will not enter into the loop
-> System.out.println("Second Max element = " + second);

-> Output : 
    Second Max element = 7
    
Hope you have understood logic behind the code😅
See you in the next coding questions👋

Secondmax.java

import java.util.Scanner;
public class Secondmax {
    //We have to find Second max number till n number withour using arrays

    public static void main(String[] args) {
        int curr, second, first , i=1;
        Scanner input = new Scanner(System.in);
        System.out.println("Enter element: ");
        curr = input.nextInt();
        second = curr;
        first = curr;
        while (i==1){
            System.out.println("Enter element: ");
            curr = input.nextInt();
            if (curr == -1) {
                i=0;
                break;
            }
            if (curr > first) {
                second = first;
                first = curr;
            }
            else if (curr > second) {
                second = curr;
            }
        }
        System.out.println("Second Max element = " + second);
    }
}