Palindrome checker. (freeCodeCamp JavaScript algorithms and data structures challenge)

Palindrome checker

function palindrome(str) {
  var newstr = str.replace(/[\W\_]/gi, "").toLowerCase();
  
  array = newstr.split("").reverse().join("");
  
  if (newstr === array) {
    return true;
  }
  else return false;
};


palindrome("eye");
// should return a boolean.

// palindrome("eye"); 
// should return true.

// palindrome("_eye"); 
// should return true.

// palindrome("race car"); 
// should return true.

// palindrome("not a palindrome"); 
// should return false.

// palindrome("A man, a plan, a canal. Panama"); 
// should return true.

// palindrome("never odd or even"); 
// should return true.

// palindrome("nope"); 
// should return false.

// palindrome("almostomla"); 
// should return false.

// palindrome("My age is 0, 0 si ega ym."); 
// should return true.

// palindrome("1 eye for of 1 eye."); 
// should return false.

// palindrome("0_0 (: /-\ :) 0-0"); 
// should return true.

// palindrome("five|\_/|four"); 
// should return false.




// freeCodeCamp javaScript algorithms and data structures challenge link is given below:

// https://www.freecodecamp.org/learn/javascript-algorithms-and-data-structures/javascript-algorithms-and-data-structures-projects/palindrome-checker