Created
June 17, 2013 00:14
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#include <iostream> | |
#include <string> | |
using namespace std; | |
long ncr(int n,int r) // This function will calculate the value of nCr | |
{ | |
if((r==0)||(n==r)) | |
return 1; | |
else | |
return (ncr(n-1,r-1)+ncr(n-1,r)); | |
} | |
int main() | |
{ | |
int n; | |
cin>>n; | |
int arr[n]; | |
for(int i=0;i<n;i++) | |
{ | |
cin>>arr[i]; | |
} | |
int q; | |
cin>>q; | |
while(q--) | |
{ | |
string s; | |
int left,right; | |
cin>>s >>left >>right; | |
if(s=="change") | |
{ | |
arr[left-1]=right; | |
continue; | |
} | |
int berries=0; | |
for(int i=left-1;i<right;i++) | |
{ | |
berries+=arr[i]; | |
} | |
int len=(right-left+1); //length of interval | |
int min_each=(berries/len); //Minimum no. og berries each will get | |
int max_num=(berries%len); // No. of people will get (min_each+1) berries | |
long res=ncr(len,max_num); //variable res will store the total no. of possible way. | |
/* | |
My algorithm are like | |
1. Distribute the berries who will get (min_each+1). | |
2. Keep going till total no. of recieptent become equal to max_num; | |
3. Distribute the rest berries into rest people. They will get min_each ammount of berries. | |
*/ | |
for(int i=0;i<max_num;i++) | |
res*=ncr((berries-(i*(min_each+1))),(min_each+1)); | |
for(int i=0;i<(len-max_num-1);i++) | |
res*=ncr((len-max_num-i)*min_each,min_each); | |
res%=3046201; | |
cout<<res<<endl; | |
} | |
return 0; | |
} |
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