Created
June 29, 2021 21:38
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an orange peel in high dimensions: what fraction of the volume does the peel comprise?
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using LinearAlgebra | |
""" | |
sample a uniform random point inside a unit orange centered at the origin. | |
* `d::Int`: dimension of the space | |
""" | |
function random_point_inside_unit_orange(d::Int) | |
x = 2 * (rand(d) .- 0.5) | |
if norm(x) < 1.0 | |
return x | |
else | |
return random_point_inside_unit_orange(d) | |
end | |
end | |
""" | |
via MC sim, determine the fraction of a unit orange that comprises the peel. | |
* `δr::Float64`: thickness of the peel | |
* `d::Int`: dimension of the space | |
* `nb_samples::Int`: # of MC samples | |
""" | |
function fraction_peel(δr::Float64, d::Int; | |
nb_samples::Int=10000) | |
nb_points_in_peel = 0 | |
for s = 1:nb_samples | |
x = random_point_inside_unit_orange(d) | |
if norm(x) > 1.0 - δr | |
nb_points_in_peel += 1 | |
end | |
end | |
return nb_points_in_peel / nb_samples | |
end | |
fraction_peel(0.1, 3) # 0.26 | |
fraction_peel(0.1, 10) # 0.65 | |
fraction_peel(0.1, 15) # =-O stack overflow, too many rejections in `random_point_inside_unit_orange` |
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