Cassidoo | isAnagram

README.md

Solution to Cassidoo's Week of July 31, 2023 Challenge

Given two strings s and t, return true if t is an anagram of s, and false otherwise. Try this in a language you're not comfortable with!

Realized there were a couple edge cases, like with anagrams involving differences in several words, but are still valid. Adjusted accordingly.

Never wrote anything in Python before, but besides being able to look up equivalent php functions in python, it was thankfully pretty one-to-one conversion.

isAnagram.php

<?php 

function isAnagram($string1, $string2) {
	$string1 = strtolower(str_replace(' ', '', $string1));
	$string2 = strtolower(str_replace(' ', '', $string2));

	if (strlen($string1) != strlen($string2)) return false;
	if ($string1 == $string2) return false;

	$arr1 = str_split($string1);
	$arr1 = asort($arr1);
	$arr2 = str_split($string2);
	$arr2 = asort($arr2);

	return ($arr1 == $arr2);
}

var_dump(isAnagram('race', 'care'));
var_dump(isAnagram('race', 'race'));
var_dump(isAnagram('barbie', 'care'));
var_dump(isAnagram('I am Lord Voldemort', 'Tom Marvolo Riddle'));

isAnagram.py

def isAnagram(string1, string2):
	string1 = string1.lower().replace(' ', '')
	string2 = string2.lower().replace(' ', '')

	if len(string1) != len(string2):
		return False
  if string1 == string2:
    return False
    
	string1 = sorted(string1)
	string2 = sorted(string2)
	
	if string1 == string2:
		return True

  return False

print(isAnagram('race', 'care'))
print(isAnagram('race', 'race'))
print(isAnagram('barbie', 'care'))
print(isAnagram('I am lord Voldemort', 'Tom Marvolo Riddle'))