Sourceless

def columns(list_of_lists):
    # Assumes all lists are same length as first, or longer
    columns = len(list_of_lists[0])
    list_of_lists = [iter(list_) for list_ in list_of_lists]
    
    for _ in xrange(columns):
        yield [list_iter.next() for list_iter in list_of_lists]

Sourceless

Aims:

• Provide a first point of contact for computer science students and computer enthusiasts in Langwith college
• Run small-scale social events based on usual group interests (video games, movies, etc.)
• Provide an open community for members to communicate, aid one another, learn, and get feedback on their work
• Promote excellence through self- and club-guided learning and competition
• Firmly set Langwith's reputation as a premier CS college

Working with HackSoc:

Sourceless

Keybase proof

I hereby claim:

• I am sourceless on github.
• I am sourceless (https://keybase.io/sourceless) on keybase.
• I have a public key whose fingerprint is 11EB 27D5 F80E 625B C383 0AB3 3D9D D96A 0340 667C

To claim this, I am signing this object: