Solution for "Forming a Magic Square" in Hackerrank

Forming a Magic Square | Solution |JavaScript.js

const magic = [
    [8, 1, 6, 3, 5, 7, 4, 9, 2],
    [6, 1, 8, 7, 5, 3, 2, 9, 4],
    [4, 3, 8, 9, 5, 1, 2, 7, 6],
    [2, 7, 6, 9, 5, 1, 4, 3, 8],
    [2, 9, 4, 7, 5, 3, 6, 1, 8],
    [4, 9, 2, 3, 5, 7, 8, 1, 6],
    [6, 7, 2, 1, 5, 9, 8, 3, 4],
    [8, 3, 4, 1, 5, 9, 6, 7, 2],
  ];
function formingMagicSquare(s) {
  const arrOneDimension = [].concat(...s);
  let min = 45;
  for (let i = 0; i < magic.length; i++) {
    let sum = 0;
    for (let j = 0; j < 9; j++) {
      const difference = Math.abs(magic[i][j] - arrOneDimension[j]);
      sum += Math.abs(magic[i][j] - arrOneDimension[j]);
    }
    if (min > sum) min = sum;
  }

  return min;
}

console.log(formingMagicSquare(s));