Created
October 30, 2012 19:44
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#include <iostream> | |
#include <stdio.h> | |
#include <string.h> | |
using namespace std ; | |
#define _(x,a) memset(x,a,sizeof(x)) | |
#define LET(x,a) __typeof(a) x(a) | |
#define FOR(i,a,b) for(LET(i,a);i!=(b);++i) | |
#define REP(i,n) FOR(i,0,n) | |
#define GI ({int t;scanf("%d",&t);t;}) | |
void crossall(int i,int j,int** mat,int n){ | |
mat[i][j]=0; //11 | |
if(i-1>=0 && j-1>=0 && mat[i-1][j-1]==1) { crossall(i-1,j-1,mat,n); } //00 | |
if(j-1>=0 && mat[i][j-1]==1) { crossall(i,j-1,mat,n); } //10 | |
if(i-1>=0 && mat[i-1][j]==1) { crossall(i-1,j,mat,n); } //01 | |
if(i+1<n && j+1<n && mat[i+1][j+1]==1) { crossall(i+1,j+1,mat,n); } //22 | |
if(j+1<n && mat[i][j+1]==1) { crossall(i,j+1,mat,n); } //12 | |
if(i+1<n && mat[i+1][j]==1) { crossall(i+1,j,mat,n); } //21 | |
if(i-1>=0 && j+1<n && mat[i-1][j+1]==1) { crossall(i-1,j+1,mat,n); } //02 | |
if(i+1<n && j-1>=0 && mat[i+1][j-1]==1) { crossall(i+1,j-1,mat,n); } //20 | |
} | |
int main(int argc, char const *argv[]) | |
{ | |
int N=GI,dim,**mat; | |
int solution[N];_(solution,0); | |
REP(l,N){ | |
dim=GI; | |
mat=new int*[dim]; | |
REP(i,dim) mat[i]=new int[dim]; | |
REP(i,dim)REP(j,dim) mat[i][j]=GI; | |
REP(i,dim)REP(j,dim) if(mat[i][j]==1) {solution[l]++;crossall(i,j,mat,dim);} | |
} | |
REP(i,N) cout<<solution[i]<<endl; | |
return 0; | |
} |
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