Maximum Odd Binary Number | Leetcode 2864

class Solution {
public:
    string maximumOddBinaryNumber(string s) {
        int count = 0;
        int n = s.size();
        for(int i=0;i<n;++i){
            if(s[i]=='1'){
                count++;
                s[i]='0';   //Reset value to 0
            }
        }
        //Remake the largest odd string
        s[n-1] = '1';
        count--;
        for(int i=0;i<n-1 and count>0;++i){
            s[i]='1';
            count--;
        }
        return s;
    }
};