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@SuvidhaMalaviya
Created April 23, 2022 08:51
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Left view of a Binary Tree is set of nodes visible when tree is visited from left side.
package GeeksDailyProblem;
import java.util.LinkedList;
import java.util.Queue;
import java.io.*;
import java.util.*;
class Node {
int data;
Node left;
Node right;
Node(int data) {
this.data = data;
left = null;
right = null;
}
}
class LeftViewBinaryTree {
static Node buildTree(String str) {
if (str.length() == 0 || str.charAt(0) == 'N') {
return null;
}
String ip[] = str.split(" ");
// Create the root of the tree
Node root = new Node(Integer.parseInt(ip[0]));
// Push the root to the queue
Queue<Node> queue = new LinkedList<>();
queue.add(root);
// Starting from the second element
int i = 1;
while (queue.size() > 0 && i < ip.length) {
// Get and remove the front of the queue
Node currNode = queue.peek();
queue.remove();
// Get the current node's value from the string
String currVal = ip[i];
// If the left child is not null
if (!currVal.equals("N")) {
// Create the left child for the current node
currNode.left = new Node(Integer.parseInt(currVal));
// Push it to the queue
queue.add(currNode.left);
}
// For the right child
i++;
if (i >= ip.length)
break;
currVal = ip[i];
// If the right child is not null
if (!currVal.equals("N")) {
// Create the right child for the current node
currNode.right = new Node(Integer.parseInt(currVal));
// Push it to the queue
queue.add(currNode.right);
}
i++;
}
return root;
}
static void printInorder(Node root) {
if (root == null)
return;
printInorder(root.left);
System.out.print(root.data + " ");
printInorder(root.right);
}
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(br.readLine());
while (t > 0) {
String s = br.readLine();
Node root = buildTree(s);
Tree g = new Tree();
ArrayList<Integer> result = g.leftView(root);
for (int value : result) {
System.out.print(value + " ");
}
System.out.println();
t--;
}
}
}
class Tree {
//Function to return list containing elements of left view of binary tree.
static int maxLevel = 0;
ArrayList<Integer> leftViewData = new ArrayList<>();
ArrayList<Integer> leftView(Node root) {
maxLevel = 0;
leftViewUtil(root, 1);
return leftViewData;
}
private void leftViewUtil(Node root, int level) {
if (root == null)
return;
if (maxLevel < level) {
leftViewData.add(root.data);
maxLevel = level;
}
leftViewUtil(root.left, level + 1);
leftViewUtil(root.right, level + 1);
}
}
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