Point-free JavaScript FizzBuzz Kata

fizzbuzz.js

var R = require('ramda');

var factorOf = R.curryN(2, R.compose(R.eq(0), R.flip(R.modulo)));

var getFizzBuzz = R.cond(
  [R.and(factorOf(3), factorOf(5)), R.always('FizzBuzz')],
  [factorOf(3),                     R.always('Fizz')],
  [factorOf(5),                     R.always('Buzz')],
  [R.T,                             R.identity]
);

var fizzBuzz = R.compose(R.map(getFizzBuzz), R.times(R.inc));

fizzBuzz(15);
// => [ 1, 2, 'Fizz', 4, 'Buzz', 'Fizz', 7, 8, 'Fizz', 'Buzz', 11, 'Fizz', 13, 14, 'FizzBuzz' ]

For those who may be confused by the errors they receive running this. Ramda (as of 0.17.1) has had some API changes:

• R.eq is now R.equals
• R.cond no longer variadic, and instead is unary so it takes an array of arrays so you need to add extra square brackets inside the cond e.g. (R.cond([[R.T,R.idenity]]);

I tweaked the code to work here

Thanks @TGOlson for a beautiful implementation.
Btw, I'm curious why not just:

 var factorOf = R.compose(R.equals(0), R.flip(R.modulo));