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Find missing Integer in array with Java
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public class MissingElement { | |
public int solution(int[] A) { | |
if (A == null) return 1; | |
else if (A.length == 0) return 1; | |
else { | |
java.util.Arrays.sort(A); | |
return evaluate(A, 0, A.length - 1); | |
} | |
} | |
int evaluate(int[] A, int start, int stop) { | |
int mid = (stop + start) / 2; | |
int expected = A[0] + mid; | |
if (start == stop) { | |
if (A[start] == (A[0] + start)) | |
if (A[0] == 1) | |
return A[0] + A.length; | |
else | |
return 1; | |
else | |
return (A[0] + start); | |
} else | |
if (A[mid] > expected) | |
return evaluate(A, start, mid); | |
else | |
return evaluate(A, mid+1, stop); | |
} | |
public static void main(String[] args) { | |
assert(new MissingElement().solution(new int[] { 1 })) == 2; | |
assert(new MissingElement().solution(new int[] { 2 })) == 1; | |
assert(new MissingElement().solution(new int[] { 1, 2 })) == 3; | |
assert(new MissingElement().solution(new int[] { 2, 3 })) == 1; | |
assert(new MissingElement().solution(new int[] { 3, 5 })) == 4; | |
assert(new MissingElement().solution(new int[] { 2, 3, 5 })) == 4; | |
assert(new MissingElement().solution(new int[] { 1, 2, 3, 5 })) == 4; | |
assert(new MissingElement().solution(new int[] { 0, 1, 2, 3, 5 })) == 4; | |
assert(new MissingElement().solution(new int[] { 0, 1, 2, 3, 5, 6 })) == 4; | |
assert(new MissingElement().solution(new int[] { 11, 13 })) == 12; | |
assert(new MissingElement().solution(new int[] { 11, 12, 14 })) == 13; | |
assert(new MissingElement().solution(new int[] { 11, 13, 14, 15, 16 })) == 12; | |
} | |
} |
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