iOS repl.it - Functions 3 Challenge Solution

functions3.swift

func isOdd(n: Int) -> Bool {
	if n % 2 != 0 {
		return true
	} else {
		return false
	}
	
	// Alternatively:
	// return n % 2 != 0
}

let testNumber = Int(readLine()!)!
let numberIsOdd = isOdd(n: testNumber)
print(numberIsOdd)

testNumber = 5
return true

//Create your function here:
func isOdd(n: Int) -> Bool {
if n % 2 == 1 {
return true
}
else {
return false
}
}

//Do not change the code below.
let testNumber = Int(readLine()!)!
let numberIsOdd = isOdd(n: testNumber)
print(numberIsOdd)

func isOdd(n: Int) -> Bool{
if n % 2 == 0{
return false
}else{
return true
}
}

% operator is my fave!

func isOdd(n: Int) -> Bool {
  return n % 2 != 0
}

func isOdd(n: Int) -> Bool { return n % 2 != 0 }

Mine is the same as 👆.

I think she wanted us in this challenge to use if else. Thats why our answer was like that, but your answers are valid too. But won't be answering the challenge using if else.

func isOdd(n: Int) -> Bool {

let n = n

if n % 2 == 0 {
return false
} else {
return true
}
}

same here

func isOdd(n: Int) ->Bool{
if (n % 2 == 0){
return false
}
else {
return true
}
}

//Do not change the code below.
let testNumber = Int(readLine()!)!
let numberIsOdd = isOdd(n: testNumber)
print(numberIsOdd)

func isOdd(n: Int) -> Bool {
if n % 2 != 0 {
return true
} else {
return false
}
}

I did exactly this code but my console was returning error. After 10min trying to understand I just realised that my B on Bool wasn't in capital letter. Damn

Solution:

func isOdd(n: Int) -> Bool {
if n%2 == 1 {
return true
} else {
return false
}
}

ha! another one

func isOdd(n: Int) -> Bool {
  if n % 2 == 0 {
    return false
  } else {
    return true
  }
}

func isOdd(n: Int) -> Bool {
// Number not divisible by 2
if n % 2 != 0 {
return true
} else {
return false
}
}

func isOdd(n: Int) -> Bool {
if n % 2 != 0 {
return true
} else {
return false
}
}

isOdd(n: 5)

BelowSolutionWorksWellButStillDontKnowWhatThisSymbol%Indicates
func isOdd(n: Int) -> Bool {

if n % 2 != 0 {
    return true
} else {
    return false
}

}
isOdd(n: 5)
isOdd(n: 7)

func isOdd(n: Int) -> Bool{
if n % 2 == 0{
return false
}else{
return true
}
}

% operator is my fave!

And how do you call this function

BelowSolutionWorksWellButStillDontKnowWhatThisSymbol%Indicates
func isOdd(n: Int) -> Bool {

if n % 2 != 0 {
    return true
} else {
    return false
}

}
isOdd(n: 5)
isOdd(n: 7)

How do you call this function ?
When I type "isOdd(n: 5)" I got "Expressions are not allowed at top level"

func isOdd(n:Int) ->Bool {
if n%2 == 0{
return true
}
else{
return false
}
}
let testno = Int(readLine()!)!
var res = isOdd(n:testno)
print(res)

This is my solution

func isOdd(n: Int) -> Bool {

    if n % 2 != 0 {
        return true
    } else {
        return false
    }
}

func isOdd(n: Int) -> Bool { return n % 5 != 0 }

let numberIsOdd = isOdd(n: 53)
print(numberIsOdd)

i used this
f```
unc isOdd (n: Int) -> Bool{
if n % 2 == 0 {
return false
}else{
return true
}
}

there is many way to make it work

THIS ONE WORKED FINE FOR ME:

func isOdd(n: Int) -> Bool {
if n % 2 == 1 {
return true
} else {
return false
}
}

func isOdd(n: Int) -> Bool {
if n.isMultiple(of: 2) {
return false
} else {
return true
}
}

func isOdd(n: Int) -> Bool {
if n % 2 == 1 {
return true
} else {
return false
}
}

isOdd(n: 5)

func isodd(n: Int) -> Bool{
if (n % 2 == 0)
{
return true
} else
{
return false
}
}
var doorShouldopen = isodd(n: 5 )
print(doorShouldopen)

A one-liner:

func isOdd(n: Int) -> Bool {
    return n & 1 == 1
}

func isOdd(n: Int) -> Bool{
if n % 2 != 0 {
return true
}else{
return false
}
}