Python Lists Coding Exercise Solution

high_scores.py

def top_three(scores):
    scores = scores
    top_scores = []
    
    # Solution
    scores.sort()
    list_size = len(scores)
    top_scores = [scores[list_size-1], scores[list_size-2], scores[list_size-3]]
    
    
    
    # Leave this line alone
    return top_scores

top_scores = sorted(scores, reverse=True)[:3]

scores = sorted(scores,reverse=True)
top_scores.append(scores[0])
top_scores.append(scores[1])
top_scores.append(scores[2])

:)

scores.sort(reverse=True)
top_scores = scores[:3]

scores.sort(reverse=True)
for score in scores:
if len(top_scores) < 3:
top_scores.append(score)

scores.sort(reverse=True)
newscores = [scores[0],scores[1],scores[2]]
top_scores.extend(newscores)

len_list=len(scores)
scores.sort(reverse=True)
for i in range(len_list):
    if i==3:
        break
    top_scores.append(scores[i])

scores.sort(reverse=True)
top_scores = [scores[0], scores[1], scores[2]]

scores.sort(reverse=True)
top_scores = [scores[0], scores[1], scores[2]]

scores.sort(reverse=True)
for i in range(3):
top_scores.append(scores[i])

scores.sort(reverse=True)
for i in range (0,3):
a = scores[i]
top_scores.append(a)

scores.sort()
scores.reverse()
top_scores = [scores[i] for i in range(len(scores)) if i < 3]