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@ThinkZ
Created February 13, 2017 00:15
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#!/usr/bin/env python
# -*- coding: utf-8 -*-
# Date: 2015/7/03
# Created by 独自等待
# 博客 http://www.waitalone.cn/
import sys, os
from Crypto.Cipher import DES
def decode_char(c):
if c == 'a':
r = '?'
else:
r = c
return ord(r) - ord('!')
def ascii_to_binary(s):
assert len(s) == 24
out = [0] * 18
i = 0
j = 0
for i in range(0, len(s), 4):
y = decode_char(s[i + 0])
y = (y << 6) & 0xffffff
k = decode_char(s[i + 1])
y = (y | k) & 0xffffff
y = (y << 6) & 0xffffff
k = decode_char(s[i + 2])
y = (y | k) & 0xffffff
y = (y << 6) & 0xffffff
k = decode_char(s[i + 3])
y = (y | k) & 0xffffff
out[j + 2] = chr(y & 0xff)
out[j + 1] = chr((y >> 8) & 0xff)
out[j + 0] = chr((y >> 16) & 0xff)
j += 3
return "".join(out)
def decrypt_password(p):
"""
huawei/h3c交换机密码破解函数
p:传入的加密密文
return: 返回明文密码
"""
r = ascii_to_binary(p)
r = r[:16]
d = DES.new("\x01\x02\x03\x04\x05\x06\x07\x08", DES.MODE_ECB)
r = d.decrypt(r)
return r.rstrip("\x00")
if __name__ == '__main__':
print '+' + '-' * 50 + '+'
print u'\t huawei/h3c交换机密码破解工具'
print u'\t Blog:http://www.waitalone.cn/'
print u'\t\t Code BY: 独自等待'
print u'\t\t Time:2015-07-03'
print '+' + '-' * 50 + '+'
if len(sys.argv) != 2:
print '用法: ' + os.path.basename(sys.argv[0]) + ' 经过加密的密文'
print '实例: ' + os.path.basename(sys.argv[0]) + ' "aK9Q4I)J\'#[Q=^Q`MAF4<1!!"'
sys.exit()
print '解密结果:' + decrypt_password(sys.argv[1])
@OnlyTuxUser
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Make sure the password is 24 characters long. Make sure that all special characters in the password are quoted with \.

@GMengZhi
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$1a$[i9,QN\e<5$;^C{ChNsREuO-HT%G!];Q;=V3(^}TP4Hh}Qn{8w*$ siphertext such as me is longer than 24 characters.

Make sure the password is 24 characters long. Make sure that all special characters in the password are quoted with .

$1a$[i9,QN\e<5$;^C{ChNsREuO-HT%G!];Q;=V3(^}TP4Hh}Qn{8w*$ mine cipherpwd longer than 24 characters,what should I do now.And I can't identify what is special characters in this situation.

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