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/** | |
* 1.3 Given two strings, write a method to decide if one is a permutation of | |
* the other. | |
* | |
* @author Jiateng | |
*/ | |
public class CC1_3 { | |
//Time O(n), Space O(1) | |
public static boolean permutation(String s1, String s2) { | |
//null should be check first | |
if (s1 == null || s2 == null) { | |
return false; | |
} | |
if (s1.isEmpty() && s2.isEmpty()) { | |
return true; | |
} | |
if (s1.isEmpty() || s2.isEmpty()) { | |
return false; | |
} | |
if (s1.length() != s2.length()) { | |
return false; | |
} | |
int[] array = new int[256]; | |
//char to int, ASCII | |
for (char c : s1.toCharArray()) { | |
//System.out.println(c); | |
//System.out.println(Integer.valueOf(c)); | |
array[c] += 1; | |
} | |
//if s1 is equal to s2, all in array will be 0 | |
for (char c : s2.toCharArray()) { | |
array[c] -= 1; | |
} | |
for (int i : array) { | |
if (i != 0) { | |
return false; | |
} | |
} | |
return true; | |
} | |
public static void main(String[] args) { | |
System.out.println(permutation("", "")); | |
System.out.println(permutation("abc", "cba")); | |
System.out.println(permutation("asf", "")); | |
System.out.println(permutation(null, "asf")); | |
} | |
} |
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