Created
June 21, 2014 19:38
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/** | |
* 1.4 Write a method to replace all spaces in a string with'%20'. You may | |
* assume that the string has sufficient space at the end of the string to hold | |
* the additional characters, and that you are given the "true" length of the | |
* string. (Note: if implementing in Java, please use a character array so that | |
* you can perform this operation in place.) EXAMPLE | |
* | |
* Input: "Mr John Smith " | |
* | |
* Output: "Mr%20Dohn%20Smith" | |
* | |
* @author Jiateng | |
*/ | |
public class CC1_4 { | |
//Time O(n), Space O(n) | |
public static String replace1(String target) { | |
StringBuilder result = new StringBuilder(); | |
char[] array = target.toCharArray(); | |
for (int i = 0; i < array.length; i++) { | |
if (array[i] != ' ') { | |
result.append(array[i]); | |
} else { | |
result.append("%20"); | |
} | |
} | |
return result.toString(); | |
} | |
//Time O(n), Space O(n) | |
public static String replace2(String target) { | |
char[] array = target.toCharArray(); | |
int len = array.length; | |
int spaceCount = 0; | |
int newLen = 0; | |
for (int i = 0; i < len; i++) { | |
if (array[i] == ' ') { | |
spaceCount++; | |
} | |
} | |
//space will be replaced by %20 | |
newLen = len + spaceCount * 2; | |
char[] newArray = new char[newLen]; | |
for (int i = len - 1; i >= 0; i--) { | |
if (array[i] == ' ') { | |
newArray[newLen - 1] = '0'; | |
newArray[newLen - 2] = '2'; | |
newArray[newLen - 3] = '%'; | |
newLen -= 3; | |
} else { | |
newArray[newLen - 1] = array[i]; | |
newLen -= 1; | |
} | |
} | |
return new String(newArray); | |
} | |
public static void main(String[] args) { | |
System.out.println(replace1(" iisfd sdfs sdfs ")); | |
System.out.println(replace2(" iisfd sdfs sdfs ")); | |
} | |
} |
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