Reporting the spam

spamreport.py

# SWAMI KARUPPASWAMI THUNNAI

import requests
import time
from bs4 import BeautifulSoup
from selenium import webdriver

browser = webdriver.Chrome()
browser.get("https://www.github.com/login")

time.sleep(10)

r = requests.get("https://github.com/akdnfbf", headers={"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:73.0) Gecko/20100101 Firefox/73.0"})  

soup = BeautifulSoup(r.content, "html.parser")
links = soup.find_all("a", class_="content-title no-underline")
url_list = []
for link in links:
	link_url = "https://github.com" + link.get("href")
	url_list.append(link_url)

message = """
This is a spam. Please close it.

Wrote a small script to automate the reporting, Just like the spammer did.

Regards,
Visweswaran N
"""

for url in url_list:
	browser.get(url)
	try:
		text = browser.find_element_by_xpath('//*[@id="new_comment_field"]')
		text.send_keys(message)
		browser.find_element_by_xpath('/html/body/div[5]/div/main/div[3]/div/div/div/div[2]/div/div[1]/div/div[2]/div/form/div/div/div/div/div[2]/button').click()
	except:
		pass # some might actually closed it