Timer problem in Python

instructions.txt

program in the file observe.py that prints out the calls for a spaceship that is about to launch. Countdown from 10 to 1 and then output Liftoff!

Your uses a for loop.

Here's a sample run of the program:

$ python3 Observe.py
10
9
8
7
6
5
4
3
2
1
Liftoff!

Run it and check the output

Now if you got an idea of how it runs then designe a digital clock using
nested loops 

the format should be hh:mm:ss

for every 0-59 total 60 seconds minites will be updated to 1 and for every 60 minutes that is 0-59 minutes hours will be updated by 1
use the previous Observe.py program and design your own logic for this

observe.py

"""
Prints out a spaceship launch sequence.
"""
import time
def main():
    for i in range(10,0,-1):
        if(i < 10):
            print("0",end="")
        print(i, end="", flush = True)
        print("\b\b",end="")
        
        time.sleep(1)
    print("Liftoff!")

if __name__ == '__main__':
    main()

timer.py

# solution code
import time
def main():
  sec = 0
  min = 0
  hr = 0
  while sec < 60:
    print("{:02d}:{:02d}:{:02d}".format(hr,min,sec), end="", flush = True)
    sec += 1
    if sec == 60:
      sec = 0
      min += 1
    if min == 60:
      min = 0
      hr += 1
    if hr == 24:
      break
    
    print("\b"*8,end="")
      
        
  print("Liftoff!")

if __name__ == '__main__':
    main()