Want to Successfully run test2

Promise-async-sync.js

const calculate = k => new Promise((resolve, reject) => {
    setTimeout(() => {
        resolve(k**3)
    }, 500)
})

const gimme_val = async (k) => {
    transformed_val = await calculate(k)
    return transformed_val
}

// async function do_test1() {
//     my_pre_built_array = [1, 2, 3]
//     my_arr = []
//     for(index = 0; index < my_pre_built_array.length; index++)
//     {
//         transformed_val = await gimme_val(my_pre_built_array[index])
//         my_arr.push(transformed_val)
//     }
//     return my_arr
// }
// do_test1().then(new_array => console.log(new_array))

function do_test2() {
    my_pre_built_array = [1, 2, 3]
    my_arr = []
    for(index = 0; index < my_pre_built_array.length; index++)
    {
        gimme_val(my_pre_built_array[index])
        .then(transformed_val => {
            my_arr.push(transformed_val)
        })
        .catch(e => console.log(e))
    }
    return my_arr
}
new_array = do_test2()
console.log(new_array)