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@Wasabules
Last active December 8, 2021 00:37
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HACHEUR
<Uh> = 1/t * integrale(ut)
<Uh> = Vs(2£-1)
(a utilisé pour savoir quand
tension positive)
Uh = Ldi/dt + Ua
<Uh> = Ua
Tension moyenne induc = 0
Ldi/dt = Vs - Ua
(equa diff)
Devient : (intégration)
Ia(t) = (Vs-Uh)/L * t + im
Ia(£t) = IM = (Vs-Uh)/L * £t + im
Delta (Ia) = IM - Im = (reponse au dessus)
Imoy = centrer
Delta Ia = autour de Imoy
Imoy = 4A
Delta I = 1.6
Imin = 4A - 1.6/2
Imax = 4A + 1.6/2
Freinage
Ua > 0
Ia < 0
T2 T4 a contrôlé
Uh ou Ua > 0, £ < 0.5
uk = 0 quand fermé
Uk = V quand ouvert
i = cst dans moteur
pour avoir I = maille
(valeur VL null sur moyenne)
fem flux constant, proportionnel vitesse angulaire
E = k* omega
E = (loi maille)
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