return the list of element that exists in 2 list

overlap.py

#!/usr/bin/python3

def main():
    a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
    b = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
    ans = list(set([num for num in a if num in a and num in b]))
    print(ans)
    
if __name__ =='__main__':
    main()