Gulp stream output iterator

gulpfile.js

//
// function
function iteratePaths(stream, start, finish, paths) {
    paths.forEach(function (path) {
        stream.pipe(gulp.dest(start + path + finish));
    });
    return stream;
}

//
// suggested usage
gulp.task('styles', function () {
    return iteratePaths(
        gulp.src('assets/css/*.scss')
            .pipe($.plumber())
            .pipe($.scss()),
        'public/projects/',
        '/css/',
        ['project_1', 'project_2', '...', 'project_N']
    )
});