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@XanClic
Created June 10, 2016 13:15
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f(x)
= (1/(σ sqrt(2π)) e^(-1/2 x^2/σ^2))''
= (1/(σ sqrt(2π)) (e^(-1/2 x^2/σ^2) · -x/σ^2))'
= 1/(σ sqrt(2π)) (e^(-1/2 x^2/σ^2) · -x/σ^2 · -x/σ^2 + e^(-1/2 x^2/σ^2) · -1/σ^2)
= 1/(σ sqrt(2π)) (e^(-1/2 x^2/σ^2) · x^2/σ^2 + e^(-1/2 x^2/σ^2) · -1/σ^2)
f(σ) = 1/(σ sqrt(2π)) (e^(-1/2) · 1 + e^(-1/2) · -1)
= 1/(σ sqrt(2π)) (e^(-1/2) - e^(-1/2))
= 0
f(-σ) = 1/(σ sqrt(2π)) (e^(-1/2) · 1 + e^(-1/2) · -1)
= 1/(σ sqrt(2π)) (e^(-1/2) - e^(-1/2))
= 0
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