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June 2, 2017 23:07
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Return biggest sum of element in subarray
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function largestOfFour(arr) { | |
var summs = []; | |
var index = 0; | |
for(var i = 0; i < arr.length; i++) { | |
summs.push(arr[i].reduce(function(prev, current, index) { | |
return prev + current; | |
})); | |
} | |
for(var j = 0; j < summs.length; j++) { | |
index = j !== 0 ? summs[j] > summs[j-1] ? j : summs[0] : summs[j]; | |
} | |
return arr[index]; | |
} | |
largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]); |
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