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/*1.3 Given two strings, write a method to decide if one is a permutation of the other. | |
space complexity: | |
time complexity: | |
date: 09/01/2014 | |
*/ | |
public class permutationString{ | |
public static boolean permutation(String s1, String s2){ | |
if(s1 ==NULL || s2 == NULL) | |
return false; | |
if(s1.isEmpty()&& s2.isEmpty()) | |
return true; | |
else if(s1.isEmpty() || s2.isEmpty()) | |
return false; | |
if(s1.length != s2.length) | |
return false; | |
int[] test = new int[256]; | |
for(char c : s1.toCharArray()){ | |
test[c] +=1; | |
} | |
for (char c : s2.toCharArray()){ | |
test[c]-=1; | |
} | |
for(int i: test){ | |
if(i!= 0) | |
return false; | |
else | |
return true; | |
} | |
} | |
} |
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