Created
February 22, 2023 15:33
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Merge Sort using cpp
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// Diego Emilio Moreno Sanchez | |
#include <iostream> | |
using namespace std; | |
void mergeSort(int arr1[], int n1, int arr2[], int n2, int arr3[]) { | |
int i = 0, j = 0, k = 0, p; | |
while (i < n1 && j < n2) { | |
if (arr1[i] < arr2[j]) { | |
arr3[k] = arr1[i]; | |
i++; | |
} else { | |
arr3[k] = arr2[j]; | |
j++; | |
} | |
k++; | |
} | |
if (i >= n1) { | |
for (p = j; p < n2; p++) { | |
arr3[k] = arr2[p]; | |
k++; | |
} | |
} else { | |
for (p = i; p < n1; p++) { | |
arr3[k] = arr1[p]; | |
k++; | |
} | |
} | |
} | |
int main() { | |
int arr1[] = {2, 4, 6, 8, 10}; | |
int arr2[] = {1, 3, 5, 7, 9}; | |
int arr3[10]; | |
int n1 = sizeof(arr1) / sizeof(arr1[0]); | |
int n2 = sizeof(arr2) / sizeof(arr2[0]); | |
mergeSort(arr1, n1, arr2, n2, arr3); | |
for (int i = 0; i < n1 + n2; i++) { | |
cout << arr3[i] << " "; | |
} | |
return 0; | |
} |
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