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def computepay(h,r): | |
if h > 40: | |
p = 1.5 * r * (h - 40) + (40 *r) | |
else: | |
p = h * r | |
return p | |
hrs = input("Enter Hours:") | |
hr = float(hrs) | |
rphrs = input("Enter rate per hour:") | |
rphr = float(rphrs) | |
p = computepay(hr,rphr) | |
print(p) |
def computepay(h, r):
if h > 40 :
p = 1.5 * r * (h - 40) + (40 * r)
else :
p = h * r
return p
hrs = input("Enter Hours:")
hr=float(hrs)
r = input("Enter Rate :")
rt = float(r)
p = computepay(hr , rt)
print("Pay",p)
def computepay(h,r):
if h > 40:
p = (1.5 * r) * (h - 40) + (40 *r)
else:
p = h * r
return p
hrs = input("Enter Hours:")
h = float(hrs)
rate = input("Enter rate per hour:")
r = float(rate)
p = computepay(h,r)
print("Pay",p)
def compute_pay(r,h):
if h <= 40:
return r * h
elif h >=40:
return 40*r+(h-40)r1.5
fhours = input('Enter hours: ')
try:
hrs = float(fhours)
frate = input('Enter rate: ')
rate = float(frate)
x = compute_pay(rate,hrs)
print(x)
why are we using 1.5 value ?
It is a good question; I forgot what the question was. :(
def computepay(h,r):
if h <= 40:
return h*r
elif h > 40:
return 40 * r +(h-40) * 1.5 * r
hrs = input("Enter Hours:")
h = float(hrs)
rate = input("Rate")
r = float(rate)
p = computepay(h,r)
print("Pay",computepay(h,r))
hrs = input("Saati gir pezo: ") h = float(hrs) hrt = input("Rate kac:") r = float(hrt)
def computepay(a, b): if (a <= 40): islem = a * b elif (a > 40): islem = 40 * b + (a-40)_b_1.5 return islem
t = computepay (h,r)
print("Pay",t)
#worked thnku
#The specific mnemonics are used intentionally
#Not sure multiplication symbol not updating
def computepay(parameter1,parameter2):
if parameter1<=40:
gpay=(argument1argument2)
elif parameter1>40:
gpay=((40argument2)+(argument1-40)(1.5argument2))
return gpay
argument=input("Enter the hours:")
rargument=input("Enter the rate:")
try :
argument1=float(argument)
argument2=float(rargument)
except :
error=("Please enter the numeric value")
print(error)
quit()
print("pay",computepay(argument1,argument2))
def computepay(h, r):
if h > 40.0:
p = (1.5 * r) * (h - 40.0) + (r * 40.0)
else:
p = r * h
return p
shrs = input('Enter Hours: ')
srate = input('Enter Rate: ')
try:
hours = float(shrs)
rate = float(srate)
except:
print('ERROR, please enter numeric input')
quit()
p = computepay(hours, rate)
print("Pay", p)
def computepay(hrs, rph):
if hrs > 40:
return(1.5rph(hrs-40)+(40rph))
elif hrs <= 40:
return(hrsrph)
hrs = input("Enter Hours:")
rph = input("rate per hour")
hr=float(hrs)
rp=float(rph)
p=computepay(hr,rp)
print("Pay",p)
For sure this will work out
def computepay(h,r):
if h>40:
reg=40r
otp=(h-40.0)1.5r
pay=reg+otp
else:
pay=hr
return pay
hrs =input ("Enter Hours:")
rate=input ("Enter Rate per Hour:")
fh= float(hrs)
fr= float(rate)
p = computepay(fh,fr)
print("Pay",p)
try:
def computepay(h, r):
if h>40:
reg=rh
otp=(h-40.0)(r*0.5)
xp=reg+otp
else:
xp=h+r
return xp
hrs = input("Enter Hours:")
h=float(hrs)
rt = input("Enter rate:")
r=float(rt)
p = computepay(h, r)
print("Pay", p)
except:
print ("bad value")
quit()
Why did you use 1.5 to multiply? I used 0.5 and i got the same answer as yours. Can you please explain?
Thanks