ege22new_python

N = 12
time = [4,3,1,7,6,3,1,2,7,8,6,6]
deps = [[0],[0],[1,2],[3],[3],[5],[4,6],[7],[0],[0],[9],[10]]
for i in range(N):
    totaltime = time[i]
    if (deps[i][0] == 0): continue
    maxdeptime = max(time[x - 1] for x in deps[i])
    totaltime += maxdeptime
    time[i] = totaltime
print(max(time))

Решение нового задания #22 ЕГЭ по информатике 2023