Created
July 23, 2018 15:42
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#include<iostream> | |
using namespace std; | |
void makeArray(int* A, int n) | |
{ | |
for(int i = 0 ; i < n ; i++) | |
cin>>A[i]; | |
return; | |
} | |
void printArray(int* A, int n) | |
{ | |
for(int i = 0 ; i < n ; i++) | |
cout<<A[i]<<" "; | |
return; | |
} | |
void Merge(int* A, int* LA, int* RA, int soA, int soL, int soR) | |
{ | |
int i = 0, j = 0, k = 0; | |
while(i < soL && j < soR) | |
{ | |
if(LA[i] < RA[j]) | |
A[k++] = LA[i++]; | |
else | |
A[k++] = RA[j++]; | |
} | |
while(i < soL) | |
A[k++] = LA[i++]; | |
while (j < soR) | |
A[k++] = RA[j++]; | |
} | |
void MergeSort(int* A, int n) | |
{ | |
int mid; | |
mid = n/2; | |
//base case | |
if(n < 2) return; | |
int leftArr[mid]; | |
int rightArr[n-mid]; | |
for(int i = 0 ; i < mid ; i++) | |
leftArr[i] = A[i]; | |
for(int i = mid ; i < n ; i++) | |
rightArr[i-mid] = A[i]; | |
MergeSort(leftArr, mid); | |
MergeSort(rightArr, n-mid); | |
Merge(A,leftArr,rightArr,n,mid,n-mid); | |
} | |
int main() | |
{ | |
int n; | |
cin>>n; | |
int A[n]; | |
makeArray(A, n); | |
MergeSort(A, n); | |
printArray(A, n); | |
} |
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