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@ZzimonNanoq
Created February 13, 2017 00:06
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Ft = 294; %gravity force
F = 2; %external force
m = 30; %weight
a = 2; %acceleration
Fh = cosd(30)*F; %external horizontal component
Fv = sind(30)*F; %external vertical component
Fvt = Ft-Fv; %resulting vertical downwards force
Fn = Fvt; %Total normal force
FnB = 0.3/0.7*Fn; %normal force under wheel B
FnA = 0.4/0.7*Fn; %normal force under wheel A
Fa = m*a; %acceleration force
Fht = Fa - Fh; %total horizontal force
FaA = 0.4/0.7 * Fht %friction on wheel A
FaB = 0.3/0.7 * Fht %friction on wheel B
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