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August 15, 2017 17:04
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Calculate potential of electrical dipole
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import numpy as np | |
print "Calculate n terms of dipolar potential: " | |
n = int(raw_input("How many terms? ")) | |
q = float(raw_input("What's the charges(C)? ")) | |
l = float(raw_input("What's the distance between the charges(m)? ")) | |
r = float(raw_input("What's the distance to the dipole(m)? ")) | |
#theta = float(raw_input("What's the angle to the dipole in radians? ")) | |
f0 = [] | |
i = 1.0 | |
j = -1 | |
w = 0.0 | |
e0 = 8.854187817 | |
f0.append(i) | |
for x in range(n): | |
i = np.divide(float(i*j),2) | |
j -= 2 | |
#print j | |
f0.append(i) | |
# print f0 | |
angles = [0,(np.pi/2),(np.pi),(3*np.pi/2),(2*np.pi)] | |
for theta in angles: | |
x = (-2*r*l*np.cos(theta))/(r*r) | |
w = 0.0 | |
for i in range(n): | |
w+= x * f0[i]/np.math.factorial(i) | |
w = w*(q/(4*np.pi*e0/1000000000000)) | |
print "U(r) = ",w," for angle ", theta |
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