Leap year calculation v.2.py

def isYearLeap(year):
    if (year % 4) == 0:
        if (year % 100) == 0:
            if (year % 400) == 0:
                return True
            else:
                return False
        else:
            return True
    else:
        return False
# Return true if year is a multiple
    # of 4 and not multiple of 100.
    # OR year is multiple of 400.
# return (((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0));

testData = [1900, 2000, 2015, 1987]
testResults = [False, True, True, False]
for i in range(len(testData)):
    yr = testData[i]
    print(yr, "->", end="")
    result = isYearLeap(yr)
    if result == testResults[i]:
        print("OK - Leap Year")
    else:
        print("Failed - Not Leap Year")


# ------------------------- x ------------------------ x -----------------

def isYearLeap(year):
    return (((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0));

days_month_normal = [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
days_month_leapyr = [0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

def daysInMonth(year, month):
    if isYearLeap(year):
        return days_month_leapyr[month]
    return days_month_normal[month]

testYears = [1900, 2000, 2016, 1987]
testMonths = [2, 2, 5, 11]
testResults = [28, 29, 31, 30]
for i in range(len(testYears)):
    yr = testYears[i]
    mo = testMonths[i]
    print(yr, mo, "->", end="")
    result = daysInMonth(yr, mo)
    if result == testResults[i]:
        print("OK")
    else:
        print("Failed")

Oh encontre lo que buscaba , gracias :)