acspike

#target photoshop 
main();
 
function main() { 
    if(!documents.length) return;
    
    var doc = app.activeDocument;
    
    try{ 
        var Path = activeDocument.path; 

acspike

from __future__ import print_function
import random, itertools, sets

## The following represents thought process and has not been subjected to rigorus proof
# Possible pairings can be represented as two varieties of cycles in the permutations of the residents due to the restriction on reflexive pairings. 
# For each permutation there is a single cycle through all 7 name and a two disjoint cycles through 3 names and 4 names respectively.
# Total unique pairings are therefore less than 7!*2 = 10080 (less because cycles of a particular permutation generate equivalent pairings)
# There are 7! permutations. Cycles through all 7 that produce equivalent pairings can be elminiated by considering only permutations that begin with a particular digit (eg. 6).
# Therefore unique pairings for cycles through all 7 generates 6! = 720  (ie 7!/7) pairings.
# Considering 3,4 cycles inside of each permutation there should be (7!/(4!*3))(4!/4) = 420

acspike

from __future__ import print_function
import random, itertools, sets

## The following represents thought process and has not been subjected to rigorus proof
# Possible pairings can be represented as two varieties of cycles in the permutations of the residents due to the restriction on reflexive pairings. 
# For each permutation there is a single cycle through all 7 name and a two disjoint cycles through 3 names and 4 names respectively.
# Total unique pairings are therefore less than 7!*2 = 10080 (less because cycles of a particular permutation generate equivalent pairings)
# There are 7! permutations. Cycles through all 7 that produce equivalent pairings can be elminiated by considering only permutations that begin with a particular digit (eg. 6).
# Therefore unique pairings for cycles through all 7 generates 6! = 720  (ie 7!/7) pairings.
# Considering 3,4 cycles inside of each permutation there should be (7!/(4!*3))(4!/4) = 420

acspike

from __future__ import print_function
import random, itertools, sets

## The following represents thought process and has not been subjected to rigorus proof
# Possible pairings can be represented as two varieties of cycles in the permutations of the residents due to the restriction on reflexive pairings. 
# For each permutation there is a single cycle through all 7 name and a two disjoint cycles through 3 names and 4 names respectively.
# Total unique pairings are therefore less than 7!*2 = 10080 (less because cycles of a particular permutation generate equivalent pairings)
# There are 7! permutations. Cycles through all 7 that produce equivalent pairings can be elminiated by considering only permutations that begin with a particular digit (eg. 6).
# Therefore unique pairings for cycles through all 7 generates 6! = 720  (ie 7!/7) pairings.
# Considering 3,4 cycles inside of each permutation there should be (7!/(4!*3))(4!/4) = 420

acspike

from __future__ import print_function
import random, itertools, sets

## The following represents thought process and has not been subjected to rigorus proof
# Possible pairings can be represented as two varieties of cycles in the permutations of the residents due to the restriction on reflexive pairings. 
# For each permutation there is a single cycle through all 7 name and a two disjoint cycles through 3 names and 4 names respectively.
# Total unique pairings are therefore less than 7!*2 = 10080 (less because cycles of a particular permutation generate equivalent pairings)
# There are 7! permutations. Cycles through all 7 that produce equivalent pairings can be elminiated by considering only permutations that begin with a particular digit (eg. 6).
# Therefore unique pairings for cycles through all 7 generates 6! = 720  (ie 7!/7) pairings.
# Considering 3,4 cycles inside of each permutation there should be (7!/(4!*3))(4!/4) = 420

acspike

// Much code borrowed from the following
// https://github.com/practicalarduino/VirtualUsbKeyboard
// http://playground.arduino.cc/Learning/SoftwareDebounce

#include "UsbKeyboard.h"

#define BUTTON_PIN 12
#define LED_PIN 13
#define KEY_SPACE 0x2C

acspike

from VideoCapture import Device
import pygame
import datetime
import glob

cam = Device()

pic_dir = './'
pic_ext = '.jpg'
pics = glob.glob(pic_dir+'*'+pic_ext)

acspike

<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script type="text/javascript">
var drawOn = function (id) {
    var lastPoint = null;
    var canvas = document.getElementById(id);
    var ctx = canvas.getContext('2d');
    ctx.lineWidth = 4;
    var offset = jQuery('#'+id).offset();

acspike

class word(object):
    def __init__(self,w):
        self.w = w
        self.key = "%02d%s" % (len(w),w)
        self.set = self._makeset(w)
    def __str__(self):
        return self.w
    def __cmp__(self,other):
        return cmp(other.key,self.key)
    def __repr__(self):

acspike

#include "UsbKeyboard.h"

#define BUTTON_PIN_RIGHT 9
#define BUTTON_PIN_LEFT  10
#define BUTTON_PIN_UP    11
#define BUTTON_PIN_DOWN  12

#define KEY_ARROW_RIGHT 0x4F
#define KEY_ARROW_LEFT  0x50
#define KEY_ARROW_UP    0x51