Leetcode 10: Regular Expression Matching (recursive + memo)
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#include <iostream> | |
#include <string> | |
#include <vector> | |
using namespace std; | |
bool isMatch(string s, string p, int is, int ip, vector<vector<int>>& dp) { | |
if (dp[is][ip] != 0) return (dp[is][ip]==2); | |
int ois = is, oip = ip; //original is and ip values | |
while (is < s.size() && ip < p.size()) { | |
if (ip+1 < p.size() && p[ip+1] == '*') { | |
while (is < s.size()) { | |
if (p[ip] != '.' && s[is] != p[ip]) {dp[ois][oip]= (isMatch(s, p, is, ip+2, dp) ? 2 : 1); return dp[ois][oip]==2;} | |
if (isMatch(s, p, is, ip+2, dp)) {dp[ois][oip]=2; return true;} | |
is++; | |
} | |
ip += 2; | |
} | |
else if (p[ip] == '.') { is++; ip++; } | |
else { //match normal (non-wildcard) character | |
if (s[is] != p[ip]) {dp[ois][oip]=1; return false;} | |
else { is++; ip++; } | |
} | |
} | |
//trailing wildcards | |
if (is==s.size() && ip+1 < p.size() && p[ip+1]=='*') { | |
dp[ois][oip] = (isMatch(s, p, is, ip+2, dp) ? 2 : 1); | |
return (dp[ois][oip] == 2); | |
} | |
bool matched = (is == s.size() && ip == p.size()); | |
dp[ois][oip] = (matched ? 2 : 1); | |
return matched; | |
} | |
bool isMatch(string s, string p) { | |
vector<vector<int>> dp (s.size()+1, vector<int>(p.size()+1, 0)); //key[is,ip] values: 0=unvisited, 1=visited false return, 2=visited true return | |
return isMatch(s, p, 0, 0, dp); | |
} | |
int main() { | |
string s = "abcaaaaaaabaabcabac"; //"a"; //"ab"; //"aa"; //"mississippi";//"aab"; | |
string p = ".*ab.a.*a*a*.*b*b*"; //".*..a*"; //".*"; //"a*"; //"mis*is*p*.";//"c*a*b"; | |
cout << isMatch(s, p) << "\n"; | |
return 0; | |
} |
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