Write a function that takes two strings (a and b) as arguments. Return the number of times a occurs in b.

search.js

/*
Write a function that takes two strings (a and b) as arguments. Return the number of times a occurs in b.

Test Cases:

myFunction('m', 'how many times does the character occur in this sentence?')
Expected 2

myFunction('h', 'how many times does the character occur in this sentence?')
Expected 4

myFunction('?', 'how many times does the character occur in this sentence?')
Expected 1

myFunction('z', 'how many times does the character occur in this sentence?')
Expected 0

Using JavaScript Search methods 
*/

function search(a,b){
    if(!a || !b){
        throw new Error("Missing arguements, Both arguements required.");
    }
    const subStr = a.replace(/[.*+?^${}()|[\]\\]/g, '\\$&');
    const re = new RegExp(subStr, "gi");
    return (b.match(re) || []).length
}

// Test cases
{
// Test Case 1: Expected 2
const expected = 2;
const result = search('m', 'how many times does the character occur in this sentence?');
console.log('Test case 1:', result === expected ? 'Passed': 'Failed');
}

{
// Expected 4
const expected = 4;
const result =search('h', 'how many times does the character occur in this sentence?')
console.log('Test case 2:', result === expected ? 'Passed': 'Failed');
}

{
    
// Expected 1
const expected = 1;
const result =search('?', 'how many times does the character occur in this sentence?')
console.log('Test case 3:', result === expected ? 'Passed': 'Failed');
}

{
    const expected = 0;
const result = search('z', 'how many times does the character occur in this sentence?');
console.log('Test case 4:', result === expected ? 'Passed': 'Failed');
}