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@adewes adewes/

Last active Aug 29, 2015
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Acht Königinnen
board_size = 8
def get_free_states(queens):
Get free board states for a set of queens
free_states = [[True]*board_size for i in range(0,board_size)]
for queen in queens:
for i in range(0,board_size):
for signs in [(1,1),(-1,-1),(1,-1),(-1,1),(1,0),(-1,0),(0,1),(0,-1)]:
if 0 <= signs[0]*i+queen[0] < board_size and 0 <= signs[1]*i+queen[1] < board_size:
free_states[queen[0]+signs[0]*i][queen[1]+signs[1]*i] = False
return free_states
all_states = []
for i in range(0,board_size**2):
x,y = i / board_size,i % board_size
all_states.append("".join(["Q" if j==i else "O" if x == True else "X" for (j,x) in enumerate(reduce(lambda x,y:x+y,get_free_states(set([(x,y)]))))]))
def get_compatible_states(state,possible_states):
Which other states can we possibly add to a given state.
compatible_states = []
for possible_state in possible_states:
compatible = True
for i in range(0,board_size**2):
if state.index("Q") >= possible_state.index("Q") or (state[i] == "Q" and possible_state[i] == "Q") or (state[i] == "Q" and possible_state[i] == "X") or (possible_state[i] == "Q" and state[i] == "X"):
compatible = False
if compatible:
return compatible_states
#Generate a "state compatibility" table, for faster lookup
compatibilities = [[all_states.index(state) for state in get_compatible_states(first_state,all_states)] for first_state in all_states]
state_indexes = dict([(state,i) for i,state in enumerate(all_states)])
def narrow_down(current_solutions,level = board_size-1):
Narrows down a list of possible solutions, recursively adding new states to the list.
for solution in current_solutions:
compatible_states = [state for state in all_states if not state in solution]
for state in solution:
compatible_states = [s for s in compatible_states if state_indexes[s] in compatibilities[state_indexes[state]]]
new_solutions = [solution + [compatible_state] for compatible_state in compatible_states]
if level > 1:
for higher_solution in narrow_down(new_solutions,level-1):
yield higher_solution
for solution in new_solutions:
yield solution
#Generate and print the solution
cnt = 0
for solution in narrow_down([[state] for state in all_states],board_size-1):
print ",".join(["%.2d" % i for i in sorted([all_states.index(state) for state in solution]) ]),"\n\n"
print "\n".join(solution),"\n"
print cnt

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adewes commented Feb 22, 2014

Solves the famous "eight queens" problem, using generators.

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