`map` using fold
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| import Tree._ | |
| def map[A,B](tree: Tree[A])(f: A => B): Tree[B] = | |
| fold(tree, Tree.empty[B]){(l, x, r) => Node(f(x), l,r)} | |
| scala> map (t1) ( x => x * 10) | |
| res11: Tree[Int] = | |
| Node(40, | |
| Node(20, | |
| Node(10,EmptyTree,EmptyTree), | |
| Node(30,EmptyTree,EmptyTree)), | |
| Node(70, | |
| Node(60,EmptyTree,EmptyTree), | |
| Node(90,EmptyTree,EmptyTree))) |
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