The TicTacToe game's ScoreBoard class is taking shape

ScoreBoard.coffee

class App.ScoreBoard
  permutations =
    [['A_1', 'B_1', 'C_1'],
     ['A_2', 'B_2', 'C_2'],
     ['A_3', 'B_3', 'C_3'],

     ['A_1', 'A_2', 'A_3'],
     ['B_1', 'B_2', 'B_3'],
     ['C_1', 'C_2', 'C_3'],

     ['A_1', 'B_2', 'C_3'],
     ['A_3', 'B_2', 'C_1']]

  result: (gameBoard) ->
    check_for_winners = (x_or_o) ->
      for permutation in permutations
        if(gameBoard.moves[permutation[0]] == x_or_o and
             gameBoard.moves[permutation[1]] == x_or_o and
               gameBoard.moves[permutation[2]] == x_or_o)
                 return true

      return false

    result = check_for_winners('x')
    return App.X_WINS if result
    result = check_for_winners('o')
    return App.O_WINS if result

    return App.UNDECIDED

I wish I {enumberable}.all? would be available in CoffeeScript. I don't like line 17-19.