Comparing a list with a function in Python

compare.py

"""Some Python code to illustrate the 'issue' noticed in JavaScript here:
http://stackoverflow.com/questions/9381321/a-function-is-larger-than-an-array

This will work on Python 2.x; in Python 3.x you would get:
TypeError: unorderable types: list() > function()
"""

l1 = []

def f():
    return 0

l2 = []

print l1 > f # True
print f > l1 # False
print str(l1) > str(f) # True, same as line 15
print str(f) > str(l1) # False, same as line 16
print l2 > f # True
print f > l2 # False