convert XML files to format can be posted via postman

escape.py

import os
if not os.path.exists('escaped'):
    os.makedirs('escaped')


def escape(file):
    with open(file, 'r') as f:
        a_string = ''.join(f)
    escaped = a_string.replace('"', '\\"')
    escaped = escaped.replace('><', '>\\r\\n<')
    file_escaped = './escaped/'+file
    f = open(file_escaped, "w")
    f.write(escaped)
    print(escaped)


files = [f for f in os.listdir('.') if f.endswith('.xml') or f.endswith('.XML')]
for file in files:
    escape(file)