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@ahogen
Last active August 16, 2017 20:27
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(0x\w{1,2})\s+0x(\w{1,2})\s+0x(\w{1,2})\s+0x(\w{1,2})

This regex will capture groups of 4 byte strings. It assumes the following:

  • All byte strings have a "0x" prefix
  • All byte strings are only seperated by white space
  • There are always two hex-digits in each byte string. Meaning a zero should always look like "0x00" and not "0x0".

Notice how each byte is in a capture group. This means you can concatenate the 4 capture groups, resulting in a 32-bit hex string.

Example:

0x01 0x7d 0x3d 0x00 
0xff 0xff 0xff 0xff 
0xfe 0xbe 0x7d 0x00 
0xff 0xff 0xff 0xff 
0xf9 0x1b 0x4c 0x00

In the Atom text editor, you can access capture groups with a dollar sign and the capture group number (see Atom issue #351). Put the regex statement above into the "Find" box, and the statement below into the "Replace" box.

$1$2$3$4, 

Now, clicking "Replace All" in Atom, should result in the following output:

0x017d3d00, 
0xffffffff, 
0xfebe7d00, 
0xffffffff, 
0xf91b4c00,
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