Skip to content

Instantly share code, notes, and snippets.

@aishraj
Forked from yuvipanda/Hint.md
Created November 13, 2011 09:59
Show Gist options
  • Save aishraj/1361924 to your computer and use it in GitHub Desktop.
Save aishraj/1361924 to your computer and use it in GitHub Desktop.
Insertion Sort Solutions (InterviewStreet CodeSprint Fall 2011)

The answer is the number of inversions in the array, which is the number of pairs i,j such that i < j and a[i] > a[j]. Counting this is a fairly classical problem with many solutions such as using data structures such as Balanced Trees or Binary Indexed Trees. Another particularly elegant solution involves modifying merge sort to count the number of inversions when merging the two sorted halves in the algorithm.

#include<iostream>
#include<stdio.h>
#include<string.h>
using namespace std ;
#define MAXN 100002
#define MAX 1000002
int n,a[MAXN],c[MAX] ;
int main()
{
int runs ;
scanf("%d",&runs) ;
while(runs--)
{
scanf("%d",&n) ;
for(int i = 0;i < n;i++) scanf("%d",&a[i]) ;
long long ret = 1LL * n * (n - 1) / 2 ;
memset(c,0,sizeof c) ;
for(int i = 0;i < n;i++)
{
for(int j = a[i];j > 0;j -= j & -j) ret -= c[j] ;
for(int j = a[i];j < MAX;j += j & -j) c[j]++ ;
}
cout << ret << endl ;
}
return 0 ;
}
@HariTejaVarma
Copy link

i did not understand 16 and 17 lines,please explain..............

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment