Created
October 27, 2014 08:58
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周回距離と速度の最小公倍数から周回距離を割ったものが全て同一であればいいはず……(しかしWA
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#include <iostream> | |
#include <utility> | |
#include <algorithm> | |
using namespace std; | |
typedef long long ll; | |
typedef pair<ll, ll> P; | |
bool alldiv(ll t, ll* nums, ll n){ | |
bool f = true; | |
for(int i = 0;i < n;++i){ | |
f = f && (t % nums[i] == 0); | |
} | |
return f; | |
} | |
ll gcd(ll n, ll m){ | |
ll mod; | |
if(n == m) return n; | |
if(n == 0 || m == 0) return 0; | |
while(m != 0){ | |
mod = n % m; | |
n = m; | |
m = mod; | |
} | |
return n; | |
} | |
ll lcm(ll n, ll m){ | |
return n / gcd(n, m) * m; | |
} | |
int main(){ | |
ll n, dist[10], v[10], divisor, ans; | |
vector<P> comb; | |
//bool f; | |
while(cin >> n, n){ | |
//f = true; | |
comb.reserve(n); | |
for(int i = 0;i < n;++i){ | |
cin >> dist[i] >> v[i]; | |
divisor = gcd(dist[i], v[i]); | |
dist[i] /= divisor; | |
v[i] /= divisor; | |
comb[i] = make_pair(dist[i], lcm(dist[i], v[i])); | |
//cout << comb[i].first << " " << comb[i].second << endl; | |
} | |
sort(comb.begin(), comb.end()); | |
for(int i = 0;i < n;++i){ | |
//cout << comb[n - i - 1].first << comb[n - i - 1].second << endl; | |
cout << comb[i].second * comb[n - i - 1].first / dist[i] << endl; | |
} | |
} | |
return 0; | |
} |
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